A piece of copper alloy with a mass of 73.0 g is
heated from 23.0◦C to 44.0◦C. In the process,
it absorbs 558 J of energy as heat. What is
the specific heat of this copper alloy?
d1231.31241
To find the specific heat of the copper alloy, we can use the equation:
Q = mcΔT
Where:
Q is the heat absorbed by the copper alloy,
m is the mass of the copper alloy,
c is the specific heat of the copper alloy, and
ΔT is the change in temperature.
In this case, we are given:
m = 73.0 g
ΔT = 44.0°C - 23.0°C = 21.0°C
Q = 558 J
We can rearrange the equation to solve for c:
c = Q / (mΔT)
Substituting the given values, we have:
c = 558 J / (73.0 g * 21.0°C)
Now we can calculate the specific heat of the copper alloy:
c = 558 J / (1533 g*°C)
c ≈ 0.364 J/(g°C)
Therefore, the specific heat of the copper alloy is approximately 0.364 J/(g°C).