How to find the mass of a solid formed when: 45.00ml solution of 0.003 800 mol/L lead (II) nitrate is mine dish a 30.00 mL solution of 0.08800 mol/L strontium iodide
Pb(NO3)2 + SrI2 => PbI2 + Sr(NO3)2
mols Pb(NO3)2 = M x L = ?
mols SrI2 = M x L = ?
Using the coefficients in the balanced equation, find the mols PbI2 formed from each starting regent; the smaller amount formed will be the correct amount. Then grams SrI2 = mols SrI2 x molar mass SrI2.