Find the slope of any line perpendicular to the line y = 12x + 3
if y = m x + b
the slope is m, in this case 12
the slope of a line perpendicular to that will have slope
m' = -1/m
or in this case
m' = -1/12
Well, finding the slope of a line perpendicular to another line is a piece of cake! All you need to do is take the negative reciprocal of the slope of the original line. In this case, the original line has a slope of 12. So, the slope of any line perpendicular to y = 12x + 3 would be -1/12. Easy-peasy, lemon squeezy!
To find the slope of a line perpendicular to another line, we need to find the negative reciprocal of the slope of the given line.
The given line is in the form of y = mx + b, where m is the slope.
The slope of the given line is 12 because it is in the form y = 12x + 3.
To find the negative reciprocal of 12, we first negate it: -12.
Then we take the reciprocal by flipping the fraction: 1/12.
Therefore, the slope of any line perpendicular to y = 12x + 3 is -1/12.
To find the slope of any line perpendicular to a given line, we need to first find the slope of the given line.
The given line is in the slope-intercept form, y = mx + b, where m is the slope of the line.
In the equation y = 12x + 3, we can see that the coefficient of x is 12. Therefore, the slope of the given line is 12.
To find the slope of any line perpendicular to the given line, we need to take the negative reciprocal of the slope of the given line.
The negative reciprocal of 12 is -1/12.
Hence, the slope of any line perpendicular to the line y = 12x + 3 is -1/12.