A carpenter is constructing a triangular roof for a storage shed as shown in the figure.
Part A
isosceles triangle = 15 degrees and 15 degrees
length of bas is 45
How high will the peaks of the rise above in the top of the shed?
b/2 = 22.5
tan(15) = h/22.5
h = 22.5(tan15)
Using tangent
Feet
Part B
After the roof a constructed, it will be covered with an asphalt roof material. The carpenter needs to calculate the combined length of the two slope sides. What will be the total length needed of the roof covering?
a = sqr(b^2 +h^2)
then add side isosceles triangle
am I right?
A. Correct.
B. Cos15 = 22.5/L1.
L1 = 22.5/Cos15 = 23.3.
Length = L1 + L2 = 23.3 + 23.3 = 46.6
the first part is wrong it is 6 because you use 22.5 divided by cos 15
Yes, you are correct in your approach. To find the height of the peaks, you can use the formula for the tangent of an angle in a right triangle:
tan(15) = h/22.5
You correctly rearranged the formula to solve for h:
h = 22.5 * tan(15)
To find the total length needed for the roof covering, you can first calculate the length of each slope side using the Pythagorean theorem:
a = √(b^2 + h^2)
Then, you can add the length of the two slope sides to get the total length needed:
total length = 2 * a + b
So, your approach is correct. Just remember to substitute the appropriate values for b and h that you calculated in Part A.