(x-r)^2 (1/r) (e^(-x/r)) from the interval negative infinity to positive infinity?
u = (x-r)^2 du = 2(x-r) dx dv = (1/r) e^(-x/r) dx v = e^(-x/r) ∫ u dv = uv - ∫ v du = (x-r)^2 e^(-x/r) - 2∫(x-r) e^(-x/r) dx Now do it all over again. Notice that the power of (x-r) has been reduced by one.
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