what volume of oxygen at 423.0K and a pressure of 127.4kPa will be produced by the decomposition of 129.7g barium peroxide to form barium oxide and oxygen gas?

Thank you

What answer

.25984L

To calculate the volume of oxygen gas produced by the decomposition of barium peroxide, we will need to use the ideal gas law. The ideal gas law is expressed as:

PV = nRT

Where:
P = pressure of the gas (in Pa)
V = volume of the gas (in m³)
n = number of moles of the gas
R = ideal gas constant (8.314 J/(mol·K))
T = temperature of the gas (in Kelvin)

Step 1: Calculate the number of moles of barium peroxide (BaO2)
To determine the number of moles of barium peroxide, we need to use its molar mass. The molar mass of barium peroxide (BaO2) is calculated by adding the atomic masses of its constituents:
Ba: 137.33 g/mol
O2: 2 × 16.00 g/mol = 32.00 g/mol

Molar mass of BaO2 = 137.33 + 32.00 = 169.33 g/mol

Now, we can calculate the number of moles using the given mass of barium peroxide:
Number of moles = mass / molar mass
Number of moles = 129.7 g / 169.33 g/mol

Step 2: Convert the temperature to Kelvin
The given temperature is given in degrees Celsius, so we need to convert it to Kelvin by adding 273.15:

T(K) = T(°C) + 273.15

T(K) = 423.0 + 273.15

Step 3: Convert the pressure to Pascals (Pa)
The given pressure is in kilopascals (kPa), so we need to convert it to Pascals by multiplying by 1000:

P(Pa) = P(kPa) × 1000

P(Pa) = 127.4 kPa × 1000

Step 4: Solve for the volume of oxygen gas (V)
Rearrange the ideal gas law equation to solve for the volume (V):

V = (nRT) / P

Substitute the known values into the equation and perform the calculation to find the volume of oxygen gas in cubic meters (m³):

V = (number of moles) × (ideal gas constant) × (temperature in Kelvin) / (pressure in Pascals)

Finally, convert the volume to liters (L) by multiplying by 1000:

Volume (L) = Volume (m³) × 1000

Following these steps, you can calculate the volume of oxygen gas produced by the decomposition of barium peroxide.

2BaO2 ==> 2BaO + O2

mols BaO2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols BaO2 to mols O2.
Then use PV = nRT and the conditions listed and solve for L O2.