The asteroid EROS has a mass of 7.4x10+15kg. A 103kg astronaut stands on the surface, 33km from the centre of the asteroid.


What weight does she experience ?
Give your answer in Newtons. Take the Gravitational constnat, G, to be 6.67x10-11.

bill nye would know the answer

To calculate the weight experienced by the astronaut on the surface of the asteroid EROS, we can use Newton's law of gravitation, which states that the gravitational force between two objects is given by:

F = (G * m1 * m2) / r^2

Where:
F is the gravitational force,
G is the gravitational constant (6.67x10^-11 N m^2/kg^2),
m1 and m2 are the masses of the two objects, and
r is the distance between their centers.

In this case, the astronaut's mass (m2) is given as 103 kg, and the mass of the asteroid EROS (m1) is given as 7.4x10^15 kg. The distance from the center of the asteroid to the surface (r) is given as 33 km, which we need to convert to meters.

First, let's convert 33 km to meters:
33 km = 33,000 m

Now we can plug these values into the formula to calculate the gravitational force:

F = (6.67x10^-11 N m^2/kg^2 * 7.4x10^15 kg * 103 kg) / (33,000 m)^2

Simplifying the equation:
F = (6.67x10^-11 N m^2/kg^2 * 7.4x10^15 kg * 103 kg) / (33,000 m * 33,000 m)
F = (6.67x10^-11 * 7.4x10^15 * 103) / (33,000 * 33,000) N

Calculating the value using a calculator or computer program:
F ≈ 332.7 N

Therefore, the astronaut would experience a weight of approximately 332.7 Newtons while standing on the surface of asteroid EROS.