Mg3N2(s) + 6H20 = Mg(OH)2(s) + 2NH3(g)
When 2 moles of H20 react
How many grams of NH3 are produced ?
clearly, 2/3 mole NH3. So, just convert that to grams.
To find the number of grams of NH3 produced when 2 moles of H2O react, we need to use stoichiometry to determine the molar ratio between H2O and NH3.
The balanced chemical equation you provided is:
Mg3N2(s) + 6H2O(l) → Mg(OH)2(s) + 2NH3(g)
From the equation, we see that the molar ratio between H2O and NH3 is 6:2 or 3:1. This means that for every 6 moles of H2O, 2 moles of NH3 are produced.
Since we have 2 moles of H2O, we can use this ratio to calculate the moles of NH3 produced:
2 moles H2O x (2 moles NH3 / 6 moles H2O) = 0.67 moles NH3
Now we need to convert moles of NH3 to grams. To do this, we need the molar mass of NH3, which is approximately 17.03 g/mol.
0.67 moles NH3 x 17.03 g/mol = 11.42 grams NH3
Therefore, when 2 moles of H2O react, approximately 11.42 grams of NH3 are produced.