According to the reaction below, how many grams of lithium oxide could be produced from 3.1 moles LiCl?
4 LiCl + O2 → 2 Li2O + 2 Cl2
Using the coefficients in the balanced equation, convert mols LiCl to mols Li2O.
Then convert mols Li2O to grams by grams = mols x molar mass = ?
To determine the number of grams of lithium oxide produced from a given number of moles of LiCl, we need to use the molar ratios from the balanced chemical equation.
The balanced chemical equation is:
4 LiCl + O2 → 2 Li2O + 2 Cl2
From the equation, we can see that 4 moles of LiCl reacts to produce 2 moles of Li2O.
Given that we have 3.1 moles of LiCl, we can set up a ratio using the molar ratios from the balanced equation:
(3.1 moles LiCl) / (4 moles LiCl) = (x moles Li2O) / (2 moles Li2O)
To solve for x, we multiply both sides of the equation by (2 moles Li2O) and divide by (4 moles LiCl):
(x moles Li2O) = (3.1 moles LiCl) / (4 moles LiCl) * (2 moles Li2O) / (1)
(x moles Li2O) = 1.55 moles Li2O
Now we can calculate the mass of Li2O using its molar mass. The molar mass of Li2O is approximately 29.88 g/mol.
Mass of Li2O = (1.55 moles Li2O) * (29.88 g/mol) = 46.362 g
Therefore, approximately 46.362 grams of lithium oxide could be produced from 3.1 moles of LiCl.
To determine the number of grams of lithium oxide (Li2O) that could be produced from 3.1 moles of lithium chloride (LiCl), we first need to use stoichiometry to find the mole ratio between LiCl and Li2O.
From the balanced chemical equation, we can see that for every 4 moles of LiCl, we obtain 2 moles of Li2O. This means that the mole ratio between LiCl and Li2O is 4:2, or simply 2:1.
Now, let's calculate the moles of Li2O that could be produced from 3.1 moles of LiCl using the mole ratio. Since the ratio is 2:1, we divide the number of moles of LiCl by 2:
(3.1 moles LiCl) / (2) = 1.55 moles Li2O
So, 3.1 moles of LiCl could produce 1.55 moles of Li2O.
To convert the moles of Li2O to grams, we need to know the molar mass of Li2O. The molar mass of Li2O is calculated by summing the atomic masses of lithium (Li) and oxygen (O) in the formula Li2O.
The atomic mass of Li is approximately 6.94 g/mol, and the atomic mass of O is approximately 16.00 g/mol.
The molar mass of Li2O = (2 * atomic mass of Li) + atomic mass of O
= (2 * 6.94 g/mol) + 16.00 g/mol
= 13.88 g/mol + 16.00 g/mol
= 29.88 g/mol
To find the mass of Li2O, we multiply the moles (1.55 moles) by the molar mass (29.88 g/mol):
Mass of Li2O = (1.55 moles) * (29.88 g/mol)
≈ 46.26 grams
Therefore, approximately 46.26 grams of lithium oxide could be produced from 3.1 moles of lithium chloride.