According to the reaction below, how many grams of lithium oxide could be produced from 3.1 moles LiCl?

To determine how many grams of lithium oxide could be produced from 3.1 moles of LiCl, we need to use stoichiometry.

First, let's write the balanced chemical equation for the reaction:
2 LiCl + O2 -> 2 LiO + Cl2

From the equation, we can see that 2 moles of LiCl are required to produce 2 moles of LiO.

Now, we can set up a proportion using the given information:
(2 moles LiO / 2 moles LiCl) = (x grams LiO / 3.1 moles LiCl)

Simplifying the equation, we find:
x = (2 moles LiO / 2 moles LiCl) * (3.1 moles LiCl)

After cancelling the units, we get:
x = 3.1 moles LiO

To convert moles of LiO to grams of LiO, we need to use its molar mass. The molar mass of LiO is 29.88 g/mol.

Using the formula: grams = moles * molar mass, we can calculate:
grams = 3.1 moles LiO * 29.88 g/mol

Calculating the result, we find that approximately 92.628 grams of lithium oxide could be produced from 3.1 moles of LiCl.