Word problem:
A house is to be built on a lot 70ft wide by 100ft deep. The shorter side of the lot faces the street. The house must be set back from the street at least 25ft. It must be 20ft from the back lot line and 10ft from each side lot line. What are the maximum length and width of the house?
**What do I do to solve this?**
You could draw a picture.
But let's take it step by step.
The lot is 70 feet wide, but the house can only be 50 feet wide. Right?
100 - 25 - 20 = 55 feet long.
yes
To solve this word problem, you need to consider the dimensions and constraints given. Let's break it down step by step:
1. Start by drawing a diagram of the lot. Use a rectangular shape to represent the lot, with the shorter side facing the street.
2. Label the dimensions given in the problem. The width of the lot is given as 70ft, and the depth (or length) of the lot is given as 100ft.
3. Next, apply the setback requirements. Since the house needs to be set back at least 25ft from the street, subtract this amount from the depth of the lot. In this case, the effective depth is 100ft - 25ft = 75ft.
4. Apply the setback requirements for the other sides of the lot as well. The house needs to be set back 20ft from the back lot line (length) and 10ft from each side lot line (width). Subtract these amounts from the effective dimensions obtained in the previous step. For the length, subtract 20ft: 75ft - 20ft = 55ft. For the width, subtract 20ft from each side: 70ft - (2 * 10ft) = 50ft.
5. The resulting dimensions, 55ft by 50ft, represent the maximum length and width of the house that can be built within the given lot with the specified setbacks.
So, the maximum length of the house is 55ft, and the maximum width is 50ft.