A 4.9 g bullet leaves the muzzle of a rifle with a speed of 332 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.85 m long barrel of the rifle?
Force x distance = final kinetic energy of bullet
The distance is the barrel length. Solve for the Force
force=(mass)(acceleration)
what is the acceleration?
a is the rate of change of velocity.
To find the force exerted on the bullet while traveling down the barrel of the rifle, we can use the principle of impulse-momentum.
Impulse is defined as the change in momentum of an object, and it can be calculated by multiplying the force applied on the object by the time interval over which the force is applied. In this case, the force is assumed constant, so we can rewrite the formula as:
Impulse = Force * time
The impulse experienced by the bullet is equal to the change in its momentum. Since the bullet starts from rest within the chamber of the rifle, its initial momentum is zero. The final momentum can be calculated using the formula:
Momentum = mass * velocity
Substituting the values, we get:
Final momentum = (4.9 g) * (332 m/s)
Now, we can equate the impulse and change in momentum:
Force * time = Final momentum - Initial momentum
Force * time = (4.9 g) * (332 m/s)
We need to calculate the time taken by the bullet to travel down the barrel. To find that, we can use the formula:
Distance = velocity * time
Rearranging the formula, we can solve for time:
Time = Distance / velocity
Time = 0.85 m / (332 m/s)
Now, substitute this value back into the equation:
Force * (0.85 m / (332 m/s)) = (4.9 g) * (332 m/s)
Simplifying the equation and converting the mass value to kilograms:
Force = ((4.9 g) * (332 m/s)) / (0.85 m)
Force = ((0.0049 kg) * (332 m/s)) / (0.85 m)
Evaluating this expression will give you the force exerted on the bullet as it travels down the 0.85 m long barrel of the rifle.