The solubility of calcium sulfate is1.90g of caso4 per liter of aquences solution at 25c. The formula weight of caso4 is 136.11 calculate the solubility product of caso4.
M CaSO4 = mols/L. You have 1 L and mols = grams/molar mass. Solve for M.
Ksp = (Ca^2+)(SO4^2-). Plug in M Ca^2+ and SO4^2- and solve for Ksp.
To calculate the solubility product (Ksp) of calcium sulfate (CaSO4), we need to use the given solubility information. The solubility is given as 1.90 g of CaSO4 per liter of aqueous solution at 25°C.
First, we need to convert the given solubility into molar solubility. We can do this by dividing the given mass by the molar mass of CaSO4.
The molar mass of CaSO4 is 136.11 g/mol, as given in the question. Therefore, the molar solubility (s) can be calculated as follows:
s = 1.90 g / 136.11 g/mol
s ≈ 0.01396 mol/L (approximately)
Now that we know the molar solubility, we can determine the solubility product (Ksp) using the formula:
Ksp = [Ca2+][SO4^2-]
Since calcium sulfate dissociates into one calcium ion (Ca2+) and one sulfate ion (SO4^2-), the molar solubility of CaSO4 can be used as the concentration of both Ca2+ and SO4^2-.
Ksp = (0.01396 mol/L) * (0.01396 mol/L)
Ksp ≈ 1.94 x 10^-4 (approximately)
Therefore, the solubility product (Ksp) of calcium sulfate (CaSO4) is approximately 1.94 x 10^-4.