A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?

well, v changes by +3.2 m/s every second.

So, what is that after 6 seconds?

nehhehbhe

A ball begins rolling down a hill from point A. It rolls to the bottom of the hill at point D, and continues rolling up the hill to point G.

To find the final velocity of the ball after 6.0 seconds, we can use the equation of motion:

v = u + at

Where:
v = final velocity
u = initial velocity (in this case, the ball starts at rest, so u = 0)
a = acceleration
t = time

Plugging in the values given in the question, we have:

v = 0 + (3.2 m/s^2) * (6.0 s)

Multiply the acceleration (3.2 m/s^2) by the time (6.0 s) to get:

v = 19.2 m/s

Therefore, the final velocity of the ball after 6.0 seconds is 19.2 m/s.