The following reaction can be written as the sum of two reactions, one of which relates to ionization energy and one of which relates to electron affinity:
Li(g)+F(g)→Li+(g)+F−(g)
What is the reaction that corresponds to the first ionization energy of lithium, Li?
Express your answer as a chemical equation.
To identify the reaction that corresponds to the first ionization energy of lithium (Li), we need to look for a reaction where Li loses an electron to form Li+.
In the given reaction Li(g) + F(g) → Li+(g) + F-(g), we can see that Li loses an electron to become Li+.
So, the reaction that corresponds to the first ionization energy of lithium can be written as:
Li(g) → Li+(g) + e-
Where Li(g) represents lithium in the gaseous state, Li+(g) represents lithium ion in the gaseous state, and e- represents an electron.
This represents the process of ionization energy, as an atom of lithium loses an electron to form a positively charged lithium ion.
In summary, the equation that corresponds to the first ionization energy of lithium is:
Li(g) → Li+(g) + e-
The reaction corresponding to the first ionization energy of lithium can be represented as:
Li(g) → Li+(g) + e−(g)
This is pretty basic stuff.
Li(g) ==> Li^+(g) + e
The equation in the problem doesn't have the electrons in it but that basic ionization equation is as I wrote it. Your answer key MAY omit the e that I have.