10000 tonnes of iron reacted in a blast furnace Fe2O3 calculate the typical mass of iron produced each day

The easy way to do this is

Step 1. 2Fe2O3 + 3C ==> 3CO2 + 4Fe

Step 2. Then don't worry about the tonnes.

Step 3. mols Fe2O3 = 10,000/molar mass Fe2O3.

Step 4. Using the coefficients in the balanced equation, convert mols Fe2O3 to mols Fe.

Step 5. Then grams Fe = mols Fe x atomic mass Fe and the answer will come out in tonnes if you started with tonnes.

You can do it the long way by changing 10,000 tonnes to grams, following Steps 3, 4, and 5 to come up with grams Fe, and add a step 6 to convert grams back to tonnes.
The answer should be the same either way.

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To calculate the typical mass of iron produced each day, we need to know the percentage of iron in Fe2O3 (iron oxide).

The molecular weight of Fe2O3 is:
2(Fe) + 3(O) = 2(55.845 g/mol) + 3(16 g/mol) = 159.69 g/mol

To determine the percentage of iron in Fe2O3, we divide the molecular weight of iron by the molecular weight of Fe2O3 and multiply by 100:
(2(55.845 g/mol) / 159.69 g/mol) x 100 = 69.93%

Therefore, Fe2O3 contains 69.93% iron.

Now, we can calculate the mass of iron produced from 10,000 tonnes of Fe2O3 each day:
Mass of iron = (69.93% / 100%) x 10,000 tonnes = 6,993 tonnes

Hence, the typical mass of iron produced each day from 10,000 tonnes of Fe2O3 is 6,993 tonnes.

To calculate the typical mass of iron produced each day in a blast furnace, we need to know the proportion of iron present in Fe2O3.

The formula Fe2O3 indicates that each molecule of Fe2O3 contains 2 atoms of iron (Fe) and 3 atoms of oxygen (O). To find the mass of iron, we need to determine the molar mass of iron (Fe), which is approximately 55.85 g/mol.

The molar mass of Fe2O3 can be calculated as follows:
2 (number of iron atoms) * 55.85 g/mol (molar mass of iron) + 3 (number of oxygen atoms) * 16.00 g/mol (molar mass of oxygen) = 159.69 g/mol.

To find the mass of iron in Fe2O3, we can set up a ratio:
(2 iron atoms / 2 iron atoms + 3 oxygen atoms) * 100% = (2/5) * 100% = 40%.

Therefore, in Fe2O3, iron represents 40% of the total mass.

To calculate the mass of iron that can be produced from 10,000 tonnes of Fe2O3, we need to multiply the total mass by the iron proportion (40% or 0.4).

Mass of iron = 10,000 tonnes * 0.4 = 4,000 tonnes.

Hence, the typical mass of iron produced each day in this scenario would be 4,000 tonnes.