If one angle of parallelogram is twice of its adjacent angle. Find angle of parallelogram.
Angle A = X Degrees.
Angle B = 2X Degrees.
x + 2x = 180o
X = 60o = A.
2X = 120o = B.
C = A = 60o. The opposite angles are =.
D = B = 120o.
A+B+C+D = 60 + 120 + 60 + 120 = 360o.
If one angle in a rhombus is 80 degrees, what is the measure of its adjacent angle?
To find the measure of an angle in a parallelogram, we need to use the property that opposite angles in a parallelogram are congruent.
Let's assume that one angle of the parallelogram is x. According to the given information, we know that an adjacent angle to x is half of its measure.
So, the adjacent angle would be (1/2) * x = x/2.
Since opposite angles in a parallelogram are congruent, the opposite angle to x would also be x/2.
Therefore, the sum of the interior angles of a parallelogram is 180 degrees. We can set up an equation to solve for x:
x + x/2 + x/2 + x = 180
Combining like terms, we have:
2x + 2x/2 = 180
Simplifying further:
2x + x = 180
3x = 180
Dividing both sides of the equation by 3:
x = 60
So, the measure of the angle in the parallelogram is 60 degrees.