You have a large amount of 8.00 M stock solution. You need 1.60 L of 3.00 M solution for an experiment. How would you prepare the desired solution without wasting any stock solution?
A.) Start with 1.60 L of water. Add stock solution until you reach a total volume of 2.56 L .
B.) Start with 0.600 L of the stock solution. Add water until you reach a total volume of 1.60 L .
C.) Start with 1.60 L of the stock solution. Add water until you reach a total volume of 4.27 L .
D.) Mix 0.800 L each of stock solution and water.
You have a large amount of 8.00 stock solution. You need 1.60 of 3.00 solution for an experiment. How would you prepare the desired solution without wasting any stock solution?
Start with 1.60 L of water. Add stock solution until you reach a total volume of 2.56 L .
Start with 0.600 L of the stock solution. Add water until you reach a total volume of 1.60 L .
Start with 1.60 L of the stock solution. Add water until you reach a total volume of 4.27 L .
Mix 0.800 L each of stock solution and water.
The correct answer is b.
Well, I must say, working with solutions can be quite tricky! But fear not, I've got a solution for you, and it doesn't involve any wasted stock solution.
To prepare a 1.60 L of 3.00 M solution, we need to carefully consider the concentrations and volumes involved. Here's what I suggest:
D.) Mix 0.800 L each of stock solution and water.
By mixing 0.800 L of the 8.00 M stock solution with 0.800 L of water, you'll end up with a total volume of 1.60 L. And since the concentrations add up, you'll have a 3.00 M solution.
So, grab your measuring tools and mix away! Just be sure to keep the ratio of stock solution to water balanced, or you might end up with some clownish results. Happy experimenting!
To prepare the desired solution without wasting any stock solution, you would follow option B - Start with 0.600 L of the stock solution. Add water until you reach a total volume of 1.60 L.
To determine the correct method for preparing the desired solution without wasting any stock solution, you need to consider the concentration of the stock solution and the desired concentration of the final solution.
In this case, you have an 8.00 M stock solution and you need a 3.00 M solution.
The concentration of a solution is determined by the amount of solute (in this case, the stock solution) divided by the volume of the solution. Thus, to obtain a lower concentration, you need to increase the volume of the solution while keeping the amount of solute constant.
Let's evaluate each option:
A.) Start with 1.60 L of water. Add stock solution until you reach a total volume of 2.56 L.
This option does not make sense because adding more water would dilute the stock solution further, resulting in a lower concentration than the desired 3.00 M.
B.) Start with 0.600 L of the stock solution. Add water until you reach a total volume of 1.60 L.
This option also does not make sense because starting with a smaller volume of the stock solution would result in an even lower concentration of solute than the desired 3.00 M.
C.) Start with 1.60 L of the stock solution. Add water until you reach a total volume of 4.27 L.
This option would result in a larger volume of the solution, but it would dilute the concentration of the stock solution further, resulting in a lower concentration than the desired 3.00 M.
D.) Mix 0.800 L each of stock solution and water.
This option seems promising because it keeps the amount of solute constant at 0.800 L but doubles the total volume of the solution. However, it may not result in the desired concentration of 3.00 M since it does not account for the original concentration of the stock solution.
Based on the given options, the correct answer would be D.) Mix 0.800 L each of stock solution and water. However, this option may not necessarily yield a 3.00 M solution. To achieve the desired concentration accurately, you would need to calculate the exact amounts of stock solution and water required based on their concentrations and the desired concentration of the final solution using the formula:
(C1V1 + C2V2) = C3V3
Where:
C1 = concentration of stock solution
V1 = volume of stock solution
C2 = concentration of water (0 M)
V2 = volume of water
C3 = desired concentration of final solution
V3 = total volume of final solution (1.60 L)
Using this formula, you can solve for the volumes of stock solution and water needed to prepare the desired concentration.