You have a large amount of 8.00 M stock solution. You need 1.60 L of 3.00 M solution for an experiment. How would you prepare the desired solution without wasting any stock solution?
You need 3*1.6 = 4.8 mols of stuff
it is 8 mols/liter
4.8 mols ( 1 liter/8 mols) = .6 liters of the strong stuff
so mix 0.6 liters of the 8 M stuff with 1 liter of water
To prepare the desired solution without wasting any stock solution, you can use the dilution formula:
C1V1 = C2V2
Given:
C1 = concentration of stock solution = 8.00 M
V1 = volume of stock solution used
C2 = concentration of desired solution = 3.00 M
V2 = final volume of desired solution = 1.60 L
Since we want to prepare the desired solution without wasting any stock solution, we can use all of the volume of the stock solution:
V1 = 8.00 M * V2 / C2
V1 = 8.00 M * 1.60 L / 3.00 M
V1 = 4.27 L
Therefore, you would need to use 4.27 L of the 8.00 M stock solution to prepare 1.60 L of the 3.00 M desired solution.
To prepare the desired 3.00 M solution without wasting any stock solution, you can use the concept of dilution. Dilution is the process of adding solvent (in this case, more solvent is the stock solution) to a concentrated solution to decrease its concentration while keeping the total amount of solute constant.
To calculate the volume of stock solution needed for the desired solution, you can use the equation:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock solution
V1 = volume of the stock solution needed
C2 = final concentration of the desired solution
V2 = final volume of the desired solution
In this case, you have:
C1 = 8.00 M (concentration of the stock solution)
V1 = unknown volume of the stock solution needed
C2 = 3.00 M (final concentration of the desired solution)
V2 = 1.60 L (final volume of the desired solution)
Rearranging the equation, we have:
V1 = (C2 * V2) / C1
Plugging in the values, we get:
V1 = (3.00 M * 1.60 L) / 8.00 M
V1 = 0.60 L
Therefore, you need to measure 0.60 L of the 8.00 M stock solution and then add enough solvent (most likely water) to make the total volume 1.60 L. This will result in a 3.00 M solution without wasting any stock solution.