A lap pool is going to be built that is 20 times long as it is wide. The builder has 150 feet of decorative tile to place along the perimeter of the pool. What are the dimensions of the pool?
Can't tell without knowing how wide the tiles are, since the border will have 4 corners. If the tiles have width w, then if the pool's width is x,
2(x+20x)+4w = 150
To find the dimensions of the pool, we can set up an algebraic equation based on the given information. Let's assume the width of the pool is "w".
According to the problem, the length of the pool is 20 times the width, which means the length is 20w.
To find the perimeter of the pool, we need to add up all the sides. The formula for the perimeter of a rectangle is P = 2L + 2W, or in this case:
Perimeter = 2(length) + 2(width)
Since we know the perimeter is 150 feet and the decorative tile goes along the perimeter, we can set up an equation:
150 = 2(20w) + 2w
Simplifying this equation:
150 = 40w + 2w
150 = 42w
To solve for "w," divide both sides of the equation by 42:
w = 150 / 42
w ≈ 3.57
So, the width of the pool is approximately 3.57 feet.
To find the length, substitute the value of "w" back into the equation:
length = 20w
length = 20 * 3.57
length ≈ 71.43
Therefore, the dimensions of the lap pool are approximately 3.57 feet by 71.43 feet.