how would I solve this on a graph?
-3x-2y=18 and 3x-y=0
how would my equations look?
y=-9+-3/2x
y=0+3x
correct?????
the first is a line downward, going through (o,9) and (6,-9)
the second is a line going upward, with a slope of 3
what would be the second line points?
could you solve it out step by step
you didn't help me...
To solve the system of equations -3x - 2y = 18 and 3x - y = 0 on a graph, you can follow these steps:
1. Rearrange each equation to get y in terms of x:
-3x - 2y = 18 => y = (-3/2)x - 9
3x - y = 0 => y = 3x
2. Plot the two equations on a graph. The first equation, y = (-3/2)x - 9, has a y-intercept of -9 (-9 is the value of y when x = 0), and a slope of -3/2 (which means for every 2 units increase in x, y will decrease by 3 units). The second equation, y = 3x, has a y-intercept of 0 (when x = 0, y is also 0), and a slope of 3 (for every unit increase in x, y will increase by 3 units).
3. Locate the point of intersection of the two lines on the graph. This point represents the solution to the system of equations.
In this case, the second equation, y = 3x, is a line passing through the origin (0,0) and has a positive slope. The first equation, y = (-3/2)x - 9, is a line with a y-intercept of -9 and a negative slope. Therefore, these two lines are parallel and will never intersect. Consequently, there is no solution to this system of equations.