solve by graphing x-2y=8 and x+2y=0
x=8+2y
points (10,1), (12,2)would be graphed
x=0-2y
points (-2,1), (-4,2)would be graphed to form a slope
i got the graphing correct but what would be the solution...how would i write it?
4,-2
x = 8 + 2 y right
x = -2 y right
so
8 + 2 y = - 2 y because both are equal to x
so
-4 y = 8
y = -2
then
x = -2 y = 4
so I get they hit at
( 4, -2)
Yes, you did not need help after all :)
To find the solution to the system of equations by graphing, we need to determine the point at which the two lines intersect. By plotting the given points on each line, we can easily find their intersection.
Given:
Equation 1: x - 2y = 8
Equation 2: x + 2y = 0
By substituting y = 1 in Equation 1, we get:
x - 2(1) = 8
x - 2 = 8
x = 8 + 2
x = 10
So, the point (10, 1) lies on Equation 1.
By substituting y = 2 in Equation 1, we get:
x - 2(2) = 8
x - 4 = 8
x = 8 + 4
x = 12
So, the point (12, 2) lies on Equation 1.
Similarly, by substituting y = 1 in Equation 2, we get:
x + 2(1) = 0
x + 2 = 0
x = -2
So, the point (-2, 1) lies on Equation 2.
By substituting y = 2 in Equation 2, we get:
x + 2(2) = 0
x + 4 = 0
x = -4
So, the point (-4, 2) lies on Equation 2.
Now, plotting these points on the graph, we observe that the lines intersect at the point (10, 1).
Therefore, the solution to the system of equations is x = 10 and y = 1.