(x + 1)(x – 3)(x – 4) = x3 – 6x2 + 5x + 12 I'm so sorry but I can't show any working for this as I don't have a clue how to factorise when there are no common letters and numbers? Thanks!
It all hinges on the distributive property. (x+1)(x-3) = x(x-3)+1(x-3) = x^2-3x + x-3 = x^2-2x-3 Now multiply that by (x-4) and you have (x^2-2x-3)(x-4) = x^2(x-4)-2x(x-4)-3(x-4) = x^3-4x^2-2x^2+8x-3x+12 = x^3-6x^2+5x+12
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