If one gram of sodium bicrbonate made it into your stomach from 1 teaspoon of baking soda, how many moles of acid could it neutralize?
mols NaHCO3 = grams/molar mass.
mols HCl=mols HCO3%-
To answer this question, we need to follow a few steps:
Step 1: Calculate the number of moles of sodium bicarbonate (NaHCO3) in one gram of the compound.
To do this, we use the formula:
moles = mass / molar mass
The molar mass of NaHCO3 can be calculated by adding up the atomic masses of its constituent elements:
Na: 22.99 g/mol
H: 1.008 g/mol
C: 12.01 g/mol
O: 16.00 g/mol (three oxygen atoms)
So, the molar mass of NaHCO3 = 22.99 + 1.008 + 12.01 + (16.00 x 3) = 84.01 g/mol
Therefore, moles of NaHCO3 = 1 g / 84.01 g/mol = 0.0119 mol (rounded to four decimal places)
Step 2: Determine the ratio of moles of hydrochloric acid (HCl) that can be neutralized by one mole of sodium bicarbonate.
According to the balanced chemical equation for the reaction between sodium bicarbonate and hydrochloric acid:
NaHCO3 + HCl → NaCl + H2O + CO2
From the equation, we can see that one mole of NaHCO3 reacts with one mole of HCl.
Step 3: Calculate the number of moles of HCl that can be neutralized by 0.0119 moles of NaHCO3.
Since the ratio in the balanced equation is 1:1, the number of moles of HCl that can be neutralized by 0.0119 moles of NaHCO3 is also 0.0119 mol.
Therefore, one gram of sodium bicarbonate from one teaspoon of baking soda can neutralize 0.0119 moles of hydrochloric acid.