In your last 23 basketball games, you attempted 101 free throws and made 66. Find the experimental probability that you make a free throw. Write the probability as a percent, to the nearest tenth of a percent.

A. 65.3%
B. 69.8%
C. 69.7%
D. 65.7%

clearly it is 66/101

Just convert that to a decimal percent.

To find the experimental probability of making a free throw, we divide the number of successful outcomes (made free throws) by the total number of trials (attempts).

In this case, the number of successful outcomes (made free throws) is 66, and the total number of trials (attempts) is 101.

Therefore, the experimental probability of making a free throw is 66/101.

To convert this probability to a percentage, we multiply it by 100.

66/101 * 100 = 65.34653465346535...

Rounded to the nearest tenth of a percent, the probability is 65.3%.

Therefore, the correct answer is A. 65.3%.

I HAVE NO IDEA