Write the following equation in slope intercept form 3x + 4y = 12

To write the equation in slope-intercept form, which has the form y = mx + b, we need to isolate y on one side of the equation.

Starting with 3x + 4y = 12, we first subtract 3x from both sides:
4y = -3x + 12

Next, we divide each term by 4 to solve for y:
4y/4 = (-3x + 12)/4

Simplifying, we get:
y = (-3/4)x + 3

So, the given equation 3x + 4y = 12 in slope-intercept form is y = (-3/4)x + 3

3 x + 4 y = 12 Subtract 3 x to both sides

3 x + 4 y - 3 x = 12 - 3 x

4 y = 12 - 3 x

4 y = - 3 x + 12 Divide both sides by 4

4 y / 4 = - 3 x / 4 + 12 / 4

y = - ( 3 / 4 ) x + 3