25.0 mL of an unknown HCl solution is titrated with 17.5 mL 0.100 M NaOH. What is the
Molarity of the HCl solution?
To find the molarity of the HCl solution, we can use the concept of stoichiometry.
First, we need to determine the moles of NaOH used in the titration. We can do this by multiplying the volume of NaOH used (17.5 mL) by its molarity (0.100 M).
(17.5 mL) * (0.100 mol/L) = 1.75 mmol
Next, we need to determine the moles of HCl in the titration. Since NaOH and HCl react in a 1:1 ratio based on their balanced equation:
HCl + NaOH -> NaCl + H2O
This means that the moles of NaOH used is equal to the moles of HCl present in the unknown solution.
Now, we convert the moles of HCl to Molarity using the volume of the unknown HCl solution (25.0 mL):
Molarity (HCl) = moles (HCl) / volume (L)
(1.75 mmol) / (25.0 mL * (1 L / 1000 mL)) = 0.07 M
Therefore, the molarity of the HCl solution is 0.07 M.