What is an equation for the line with slope The fraction two thirds.and y-intercept 9? (1 point)
y = The fraction two thirds times x.x
y = 9x
y = The fraction two thirds times x.x + 9
y = 9x + The fraction two thirds.
6. What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)? (1 point)
y = 3x + 1
y = x – 3
y = 2x + 5
y = 2x – 5
for connexus its y = The fraction two thirds times x.x + 9
or C
you always start with y, multiply the slope by x, and add the intercept because that is the origin point
Damon's completely correct
y = m x + b
well, that is easy
y = (2/3) x + 9
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(y - -3)/(x - 1) = (1 - - 3)/(3-1)
(y+3)/(x-1) = 4/2 = 2
y+3 = 2x-2
y = 2 x - 5
To find the equation of a line given its slope and y-intercept, you can use the slope-intercept form of a linear equation:
y = mx + b
Where:
- m represents the slope of the line
- b represents the y-intercept
For the first question, where the slope is two-thirds and the y-intercept is 9:
The slope, two-thirds, can be written as a fraction: 2/3. The y-intercept is 9.
Substituting these values into the formula, we get:
y = (2/3)x + 9
Therefore, the correct answer is: y = (2/3)x + 9.
For the second question, where the line passes through the points (1, -3) and (3, 1):
First, calculate the slope using the formula:
m = (y2 - y1) / (x2 - x1)
m = (1 - (-3)) / (3 - 1)
m = 4 / 2
m = 2
Now that we have the slope, we need to find the y-intercept. Let's select one of the points, (1, -3), and substitute the values into the slope-intercept form:
-3 = 2(1) + b
-3 = 2 + b
b = -3 - 2
b = -5
Now we have both the slope, 2, and the y-intercept, -5. Substituting these values into the formula, we get:
y = 2x - 5
Therefore, the correct answer is: y = 2x - 5.