A heart defibrillator passes 10.0 A through a patient’s torso for 5.00 ms in an attempt to restore normal beating. Find the temperature increase caused in the 8.00 kg of affected tissue if all the energy heats up the tissue with a specific heat capacity of 3000 J kg-1 K-1.
To find the temperature increase caused in the affected tissue, we need to use the formula for calculating the change in temperature using heat transfer:
ΔQ = m * c * ΔT
where:
ΔQ is the amount of heat transferred,
m is the mass of the affected tissue,
c is the specific heat capacity of the tissue, and
ΔT is the change in temperature.
In this case, we are given:
m = 8.00 kg (mass of affected tissue)
c = 3000 J kg^(-1) K^(-1) (specific heat capacity of tissue)
We need to find ΔT, which is the change in temperature caused by the transfer of heat.
To calculate ΔQ, we can use Ohm's law and the equation for electrical power:
P = I^2 * R
where:
P is the power,
I is the current passing through the tissue (10.0 A), and
R is the resistance of the tissue.
Since power is defined as the rate of energy transfer, we can calculate the energy transferred as:
E = P * t
where:
E is the energy transferred,
P is the power, and
t is the time (5.00 ms).
Substituting the given values, we have:
P = I^2 * R
E = P * t
We need to calculate R (resistance). The formula for resistance is:
R = V / I
where:
V is the voltage across the tissue.
Since the voltage is not given, we need more information to calculate the resistance and subsequently the amount of energy transferred.
Please provide any additional information available or check if there might be missing data in the problem statement.