1.Find the length of the hypotenuse of a right triangle with the legs of 9cm and 12cm
A.8
B.21
C.15***
D.225
2.The length of a hypotenuse of a right triangle is 13cm. The length of one leg is 5cm. Find the length of the other leg.
A.14
B.144
C.8
D.12***
3.Which of the triangles described in the table are a right triangle?
Triangle | Side 1 | Side 2 | Side3 |
Q | 25 | 20 | 15 |
R | 26 | 20 | 14 |
S | 25 | 20 | 1026 |
T | 25 | 26 | 650 |
Answer choices:
A. (Q)****
B. (R)
C.(S)
D.(T)
4.Point E is located at point (-2, 2) and point F is located at (4, -6). What is the distance between point E to F?
A.52 squared
B.28 squared
C.10***
D.20 squared
5. Craig used the diagram to compute the distance from Ferris to Dunlap to Butte. How much shorter is the distance directly from Ferris to Butte than the distance Craig found? (1 point)
14 mi
28 mi***
70 mi
98 mi
6. In which quadrant is the point (x,y) located if x is negative and y is positive?
II***
III
IV
I
7.Point A(8,-10) is reflected over the Y-axis. Write the coordinates of A
-8,-10***
8,10
8,10
-8,10
8.How many lines of symmetry does the figure have below? If there are no lines
Of symmetry choose NONE
Shape: Pentagon
1
5***
10
none
http://www.jiskha.com/display.cgi?id=1446934898
All correct, except I can't tell #5 , no diagram can be shown in this format
Number is 8 is none I just took the test I know.
the answer is 5 and I am 100 percent sure of that Reiny is correct, and the answer to number five is 28.
1. To find the length of the hypotenuse of a right triangle, you can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the two legs. In this case, the legs are 9cm and 12cm. So, you can square each leg: 9cm^2 = 81cm^2 and 12cm^2 = 144cm^2. Then, you add these two values together: 81cm^2 + 144cm^2 = 225cm^2. Finally, you take the square root of the sum to find the length of the hypotenuse: √225cm^2 = 15cm. Therefore, the answer is C. 15.
2. Again, to find the length of the other leg of a right triangle, you can use the Pythagorean theorem. The hypotenuse is given as 13cm, and one leg is 5cm. Let's call the length of the other leg x. So, using the Pythagorean theorem, we have: x^2 + 5cm^2 = 13cm^2. Simplifying this equation, we have: x^2 + 25cm^2 = 169cm^2. Solving for x by subtracting 25cm^2 from both sides, we get: x^2 = 144cm^2. Taking the square root of both sides, we have: x = √144cm^2 = 12cm. Therefore, the length of the other leg is 12cm. The answer is D. 12.
3. In order to determine which triangle is a right triangle, we need to check if the lengths of its sides satisfy the Pythagorean theorem. For a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
Checking the given table:
Triangle Q: Side1^2 + Side2^2 = 25^2 + 20^2 = 625 + 400 = 1025 ≠ Side3^2.
Triangle R: Side1^2 + Side2^2 = 26^2 + 20^2 = 676 + 400 = 1076 ≠ Side3^2.
Triangle S: Side1^2 + Side2^2 = 25^2 + 20^2 = 625 + 400 = 1025 ≠ Side3^2.
Triangle T: Side1^2 + Side2^2 = 25^2 + 26^2 = 625 + 676 = 1301 ≠ Side3^2.
So, triangle Q is the only one that satisfies the Pythagorean theorem and is a right triangle. The answer is A. (Q)
4. To find the distance between two points in a coordinate plane, you can use the distance formula. The distance formula is given by: √((x2 - x1)^2 + (y2 - y1)^2), where (x1, y1) and (x2, y2) are the coordinates of the two points.
In this case, point E is located at (-2, 2) and point F is located at (4, -6). Using the distance formula, we have: √((4 - (-2))^2 + (-6 - 2)^2) = √((4 + 2)^2 + (-6 - 2)^2) = √(6^2 + (-8)^2) = √(36 + 64) = √100 = 10. Therefore, the distance between point E to F is 10 units. The answer is C. 10.
5. To determine how much shorter the distance directly from Ferris to Butte is compared to the distance Craig found, we need to calculate the difference between the two distances.
From the given options, the shortest distance directly from Ferris to Butte is 28 mi. According to the question, Craig found a longer distance. Therefore, we need to subtract the shorter distance, 28 mi, from the longer distance Craig found.
If the longer distance is not provided, it is not possible to determine the exact difference. However, based on the information given, the answer would be B. 28 mi, as it is the only option that corresponds to a shorter distance.