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An object has an initial velocity of 2.25 m/s at 57.2 degrees. An acceleration of 133.4 m/s/s at 59.5 degrees is applied. What was the final speed after the object has a displacement of 8.8 m at 33.5 degrees?
1 answer
Vf^2 = Vo^2 + 2a*d.
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