A number cube is rolled with these results: 64 ones, 67 twos, 73 threes, 59 fours, 72 fives, and 71 sixes. What is the experimental probability of rolling an even number?
Write your answer as a percent, to the nearest tenth of a percent...
A. 51.9%
B. 48.5%
C. 53.6%
D. 46.8%
EXPLAIN IT TOO PLEASE :)
THANK YOU TO WHOEVER HELPS ME!!
(67+59+71)/(64+67+73+59+72+71)
what's the answer
I got 48.5 I hope its correct
To find the experimental probability of rolling an even number, we need to determine the number of times an even number occurs and divide it by the total number of rolls.
First, we add up the number of twos, fours, and sixes:
67 twos + 59 fours + 71 sixes = 197
Next, we add up the total number of rolls:
64 ones + 67 twos + 73 threes + 59 fours + 72 fives + 71 sixes = 406
Now, we divide the number of even numbers (197) by the total number of rolls (406):
197 / 406 ≈ 0.4847
Finally, we convert the decimal to a percent by multiplying by 100:
0.4847 * 100 ≈ 48.5
Therefore, the experimental probability of rolling an even number is approximately 48.5%. Thus, the correct answer is B. 48.5%.