the viewing window is defined by -3 is less than or equal to x is less than or equal to 7 and 10 is less than or equal to y is less than or equal to 30. give the approximate coordinates of a) the x-intercepts, b) the y-intercepts and c) the relative minimum point. Round to the nearest whole number
You have defined a viewing windoow in x,y space but something is missing from your question. In order to have axis-intercepts and a minimum, you have to define a function that plots some sort of curve in the viewing winsdow
To find the approximate coordinates of the x-intercepts, y-intercepts, and the relative minimum point within the given viewing window, follow these steps:
a) To find the x-intercepts:
- Remember that the x-intercepts occur where y equals zero.
- So, set y = 0 and solve for x within the given viewing window.
- From the given viewing window: -3 ≤ x ≤ 7.
- By substituting y = 0, we get -3 ≤ x ≤ 7.
b) To find the y-intercepts:
- Remember that the y-intercepts occur where x equals zero.
- So, set x = 0 and solve for y within the given viewing window.
- From the given viewing window: 10 ≤ y ≤ 30.
- By substituting x = 0, we get 10 ≤ y ≤ 30.
c) To find the relative minimum point:
- The relative minimum point occurs at the lowest point of the function within the given viewing window.
- Since an actual function is not provided, I assume you are looking for a general approach.
- One way to find the relative minimum point is by graphing the function or using calculus techniques, such as finding the derivative and setting it equal to zero.
- Without the specific function, it is challenging to give the exact relative minimum point.
Please provide the function or any additional information if you need a specific relative minimum point.