what is the solution to this problem?
-2=2x^2-7x
negative two equals two times "x" squared minus seven "x".
arrange it to look like the standard quadratic
2x^2 - 7x + 2 = 0
now use the quadratic formula
x = (7 ± √33)/4
thanx
To find the solution to the equation -2 = 2x^2 - 7x, we need to solve for the value of x. Here's how you can do it step by step:
Step 1: Set the equation equal to zero by moving the -2 to the right side:
2x^2 - 7x + 2 = 0
Step 2: Factor the quadratic equation, if possible. In this case, the equation cannot be factored easily, so we'll move on to the next step.
Step 3: Use the quadratic formula, which is x = (-b ± √(b^2 - 4ac)) / (2a), where "a," "b," and "c" are the coefficients in the quadratic equation ax^2 + bx + c = 0.
For our equation, a = 2, b = -7, and c = 2, so substituting those values into the quadratic formula, we get:
x = (-(-7) ± √((-7)^2 - 4 * 2 * 2)) / (2 * 2)
x = (7 ± √(49 - 16)) / 4
x = (7 ± √33) / 4
So the solutions to the equation -2 = 2x^2 - 7x are:
x = (7 + √33) / 4
x = (7 - √33) / 4