How many moles of carbon monoxide gas are produced from the reaction of 5.00 moles of SnO2(s) with 9.00 moles of carbon according to the equation below?
SnO2(s) + 2C(s) → Sn(s) + 2CO(g)
Question 28 options:
4.50 mol
9.00 mol
18.0 mol
5.00 mol
7.50 mol
18.0 mol
To determine the moles of carbon monoxide gas produced, we need to use the balanced equation and stoichiometry.
From the balanced equation: SnO2(s) + 2C(s) → Sn(s) + 2CO(g)
We can see that for every 1 mole of SnO2 reacts, 2 moles of CO gas are produced.
Given that we have 5.00 moles of SnO2 and 9.00 moles of carbon, we need to determine which reactant is the limiting reagent.
The stoichiometric ratio between SnO2 and carbon is 1:2. So, if all the SnO2 reacts, it would require 2 x 5.00 = 10.00 moles of carbon.
Since we only have 9.00 moles of carbon, it is the limiting reagent. This means that only 4.50 moles of SnO2 will react completely.
Therefore, the maximum moles of CO produced will be 2 x 4.50 = 9.00 mol.
The correct answer is 9.00 mol.
To calculate the number of moles of carbon monoxide gas produced from the given reaction, we need to use the stoichiometry of the reaction.
The stoichiometry tells us that for every 1 mole of SnO2, 2 moles of carbon react to produce 2 moles of CO.
Given that we have 5.00 moles of SnO2 and 9.00 moles of carbon, we can calculate the number of moles of CO produced as follows:
First, we determine the limiting reactant by comparing the ratio of moles of SnO2 to moles of carbon. In this case, the ratio is 5.00 moles SnO2 to 9.00 moles carbon, or 5.00/9.00.
Since the mole ratio of SnO2 to carbon is 1:2, we multiply the mole ratio by the number of moles of carbon to find the maximum number of moles of SnO2 that can react. In this case, 5.00 moles SnO2 × (2 moles CO/1 mole SnO2) = 10.00 moles CO.
Since the number of moles of SnO2 (5.00 moles) is less than the maximum number of moles of SnO2 that can react (10.00 moles), the limiting reactant is SnO2. This means that SnO2 will determine the amount of CO produced.
The mole ratio between SnO2 and CO is 1:2, so the number of moles of CO produced is equal to the number of moles of SnO2 multiplied by the mole ratio. In this case, 5.00 moles SnO2 × (2 moles CO/1 mole SnO2) = 10.00 moles CO.
Therefore, the answer is 10.00 moles of carbon monoxide gas.