1)Find the length of the hypotenuse of a right triangle with legs of 9cm and 12cm
8 cm
21 cm
15 cm****
225 cm
2)The length of the hypotenuse of a right triangle is 13 cm. The length of one leg is 5 cm. Find the length of the other leg. (1 point)
14 cm
144 cm
8 cm
12 cm***
4.Point E is located at (–2, 2) and point F is located at (4, –6). What is the distance between points E and F?
a. square root of 52
b. square root of 28
c. 10***
d. square root of 20
Your first two answers are right.
I don't know the answer for 4.
you got them all right
whats number 3?
whats the rest?
To find the length of the hypotenuse of a right triangle, you can use the Pythagorean theorem. The Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the two legs.
For the first question, we have a right triangle with legs of 9 cm and 12 cm. To find the length of the hypotenuse, we can use the formula:
hypotenuse^2 = leg1^2 + leg2^2
Substituting the given values:
hypotenuse^2 = 9^2 + 12^2
hypotenuse^2 = 81 + 144
hypotenuse^2 = 225
Taking the square root of both sides to solve for the hypotenuse:
hypotenuse = square root of 225
Therefore, the length of the hypotenuse is 15 cm.
For the second question, we have a right triangle with a hypotenuse of 13 cm and one leg of 5 cm. Again, we can use the Pythagorean theorem to find the length of the other leg.
Using the same formula:
hypotenuse^2 = leg1^2 + leg2^2
Substituting the given values:
13^2 = 5^2 + leg2^2
169 = 25 + leg2^2
144 = leg2^2
Taking the square root of both sides to solve for the other leg:
leg2 = square root of 144
Therefore, the length of the other leg is 12 cm.
For the third question, we can use the distance formula to find the distance between points E and F in a coordinate plane.
The distance formula is given by:
distance = square root of ((x2 - x1)^2 + (y2 - y1)^2)
Substituting the given coordinates:
distance = square root of ((4 - (-2))^2 + (-6 - 2)^2)
distance = square root of (6^2 + (-8)^2)
distance = square root of (36 + 64)
distance = square root of 100
Therefore, the distance between points E and F is 10 units.