How many grams of NaOH are in 500mL of a 0.50 M solution?

500mL=.5L
MM NaOH = 39.99711g
M x V = n
0.5 x 0.5 = .25moleNaOH

.25moleNaOH x (39.99711gNaOH / 1moleNaOH) = 10.gNaOH

Is this right? If not, please tell me what I did wrong.

Never mind. I got it. Sorry

I answered this for you below much earlier in the day.

Your calculation is correct. To find the mass of NaOH in 500 mL of a 0.50 M solution, you followed the correct steps.

First, you converted the volume from milliliters (mL) to liters (L) by dividing by 1000: 500 mL = 0.5 L.

Next, you used the formula Molarity (M) multiplied by Volume (V) to find the number of moles (n) of NaOH in the solution: 0.50 M x 0.5 L = 0.25 moles of NaOH.

Then, you used the molar mass of NaOH (39.99711 g/mol) to convert moles to grams: 0.25 moles x (39.99711 g/1 mole) = 9.99928 g ≈ 10 g of NaOH.

So, your calculation is correct, and there is approximately 10 grams of NaOH in 500 mL of a 0.50 M solution. Well done!