Joey has 4 pairs of pants,6 shirts, and 2 pairs of shoes, but only 1 favorite pair of pants, 1 favorite shirt, and 1 pair of shoes. If he randomly selects an outfit to wear, what it the probability that it will be his favorite pants, shirt, and shoes?
number of ways to select an outfit
= 4x6x2
= 48 ways, only one of those is his favourite
prob of favourite = 1/48
That's what I thought but the answer in the book says 1/3.
Have yet to find a mathbook that did not contain at least one error
To find the probability that Joey randomly selects his favorite pants, shirt, and shoes, we need to determine the total number of possible outfits and the number of outfits that include his favorites.
First, let's calculate the total number of possible outfits. Joey has 4 pairs of pants, 6 shirts, and 2 pairs of shoes. To find the total number of outfits, we multiply the number of choices for each item: 4 * 6 * 2 = 48.
Next, let's determine the number of outfits that include Joey's favorite pants, shirt, and shoes. Since he has 1 favorite pair of pants, 1 favorite shirt, and 1 pair of shoes, there is only one combination that includes his favorites.
Therefore, the probability of Joey selecting his favorite pants, shirt, and shoes is 1 out of 48, or 1/48.