Determine the number of grams of water in 7.00 g of copper(II) sulfate pentahydrate.
The easy way;
determine the moles of copperII sulfate penathydrate in 5 grams.
moles=7.00/molmass=7.00/159.6
massofH2O=molesabove*5*18grams/mole
wow, okay. Thank you!
To determine the number of grams of water in a given amount of copper(II) sulfate pentahydrate, you need to first understand the chemical formula of the compound.
The chemical formula of copper(II) sulfate pentahydrate is CuSO4 · 5H2O. This means that for every one formula unit of copper(II) sulfate pentahydrate, there are five water molecules attached to it.
To calculate the number of grams of water in 7.00 g of copper(II) sulfate pentahydrate, you can follow these steps:
Step 1: Calculate the molar mass of copper(II) sulfate pentahydrate.
The molar mass is the sum of the atomic masses of all the atoms in a compound.
The molar mass of copper (Cu) is approximately 63.55 g/mol.
The molar mass of sulfur (S) is approximately 32.07 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
The molar mass of hydrogen (H) is approximately 1.01 g/mol.
Summing up the molar masses of each atom in the compound:
(1 × molar mass of Cu) + (1 × molar mass of S) + (4 × molar mass of O) + (10 × molar mass of H)
= (1 × 63.55 g/mol) + (1 × 32.07 g/mol) + (4 × 16.00 g/mol) + (10 × 1.01 g/mol)
= 249.69 g/mol
Therefore, the molar mass of copper(II) sulfate pentahydrate is approximately 249.69 g/mol.
Step 2: Convert the given mass of copper(II) sulfate pentahydrate to moles.
To do this, divide the given mass of copper(II) sulfate pentahydrate by its molar mass.
Moles = Mass / Molar Mass
Moles = 7.00 g / 249.69 g/mol
Moles ≈ 0.0280 mol
Step 3: Calculate the number of moles of water in the given amount of copper(II) sulfate pentahydrate.
Since the molar ratio between copper(II) sulfate pentahydrate and water is 1:5, multiply the number of moles of copper(II) sulfate pentahydrate by 5.
Moles of water = 0.0280 mol × 5
Moles of water = 0.140 mol
Step 4: Convert the moles of water to grams.
To do this, multiply the number of moles of water by its molar mass.
Mass = Moles × Molar Mass
Mass = 0.140 mol × 18.015 g/mol
Mass ≈ 2.52 g
Therefore, there are approximately 2.52 grams of water in 7.00 grams of copper(II) sulfate pentahydrate.