Pq and R are point in the same horizontal plane.the bearing of Q from P is 150% and the bearing of R from Q is 060%.if line (PQ)is 5cm and line (QR)is 3cm find the bearing of R from P correct to nearest degree

As always, draw a diagram.

The x- and y- components of the distances are

PQ:<5cos60°,-5sin60°>
QR:<3cos30°,3sin30°>
add them up to get PR. The find its magnitude and direction.

To find the bearing of R from P, we need to add up the bearings of Q from P and R from Q.

Given:
Bearing of Q from P = 150%
Bearing of R from Q = 060%

First, let's convert the bearing of Q from P into degrees.
150% = 150/100 = 1.5
Bearing of Q from P = 1.5 × 360° = 540°

Next, let's find the bearing of R from P.
Since the bearing of Q from P is in the same horizontal plane, the bearing of R from P can be found by adding the bearings of Q from P and R from Q.
Bearing of R from P = Bearing of Q from P + Bearing of R from Q
Bearing of R from P = 540° + 60° = 600°

So, the bearing of R from P is 600°.