A 1500 kg car is moving 18 m/s how much force is required to bring the car to a stop in 12 seconds
force*timeinSeconds=mass*changeinVelocity
2250
You can't break my car..
To calculate the force required to bring the car to a stop, we can use Newton's second law of motion. This law states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration is the change in velocity per unit time.
First, we need to find the acceleration (a). To do this, we can use the equation:
a = (final velocity - initial velocity) / time
Given:
Mass (m) = 1500 kg
Initial velocity (u) = 18 m/s
Time (t) = 12 s
Final velocity (v) = 0 m/s (as the car is coming to a stop)
Plugging the values into the equation, we have:
a = (0 m/s - 18 m/s) / 12 s
a = (-18 m/s) / 12 s
a = -1.5 m/s^2 (negative sign indicates deceleration)
Now, we can calculate the force (F) using the equation:
F = m * a
Plugging in the values, we have:
F = 1500 kg * (-1.5 m/s^2)
F = -2250 N
Therefore, the force required to bring the car to a stop in 12 seconds is 2250 Newtons, in the opposite direction of its initial velocity.