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Algebra

Austin drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
8 hours. When Austin drove home, there was no traffic and the trip only took
5 hours. If his average rate was
21 miles per hour faster on the trip home, how far away does Austin live from the mountains?
Do not do any rounding.

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  1. speed on first leg ---- x mph
    speed on return trip -- x+21 mph

    distance on first leg = 8x
    distance for return leg = 5(x+21)
    but the distances are equal, so

    8x = 5(x+21)
    8x = 5x + 105
    3x=105
    x = 35

    distance = 8(35) = 280 miles

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  2. Just realized I did this same question a few weeks back

    http://www.jiskha.com/display.cgi?id=1443062344

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