Algebra

Austin drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
8 hours. When Austin drove home, there was no traffic and the trip only took
5 hours. If his average rate was
21 miles per hour faster on the trip home, how far away does Austin live from the mountains?
Do not do any rounding.

asked by Roger
  1. speed on first leg ---- x mph
    speed on return trip -- x+21 mph

    distance on first leg = 8x
    distance for return leg = 5(x+21)
    but the distances are equal, so

    8x = 5(x+21)
    8x = 5x + 105
    3x=105
    x = 35

    distance = 8(35) = 280 miles

    posted by Reiny
  2. Just realized I did this same question a few weeks back

    http://www.jiskha.com/display.cgi?id=1443062344

    posted by Reiny

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