I have 4 spinners each divided into 4 equal sections (labeled 1,2,3,4,) what is the probability of not all same? i have tried multiple ways of doing this and get different results and i don't know what is correct. I have tried 1/4*1/3*1/2*1 and got 1/24 but i know this is incorrect because that is the same as 3 spinners instead of 4. I have tried 1/4*1/3*1/3*1/3 and i don't understand that but that's what some website told me to do and got something completely different. HELP!!!!!!!!!!!!!!!!!
the answer i need help on is if sandra flips the coin 20 times how many times can sandra expect the coin to land on tails.
Mrs. Pharr tosses a coin and spins a 2 section spinner labeled 1 and 2. What is the probability that she will flip heads and land on a 2?
To calculate the probability of not all spinners landing on the same number, we need to consider the number of favorable outcomes (the ones that meet the condition) and the total number of possible outcomes.
Let's break down the problem into steps:
Step 1: Calculate the probability of any one spinner not landing on a specific number (let's say number 1). Since there are 4 equal sections and we want to avoid the number 1, the probability of any single spinner not landing on 1 is 3/4.
Step 2: Since we want to avoid all the spinners landing on the same number, we need all four spinners to not land on 1.
To calculate the probability of all four spinners not landing on 1, we multiply the individual probabilities together:
(3/4) * (3/4) * (3/4) * (3/4) = (81/256) ≈ 0.316
So, the probability of not all spinners landing on the same number is approximately 0.316 or 31.6%.
Please note that this solution assumes that the spinning of each spinner is independent and that the spinners are fair (equally likely to land on any section).
Pr(allsame)=1*1/4*1/4*1/4
pr(not all the same)=1-pr(all same)