An experiment requires 0.34 M NH3(aq). The

stockroom manager estimates that 15 L of
the base is needed. What volume of 15 M
NH3(aq) will be used to prepare this amount
of 0.34 M base?

To calculate the volume of 15 M NH3(aq) required to prepare 0.34 M NH3(aq), we can use the concept of molarity and the dilution equation:

C1V1 = C2V2

Where:
C1 = Initial concentration (15 M NH3(aq))
V1 = Initial volume (unknown)
C2 = Final concentration (0.34 M NH3(aq))
V2 = Final volume (15 L)

We rearrange the equation to solve for V1:

V1 = (C2V2) / C1

Substituting the given values:

V1 = (0.34 M * 15 L) / 15 M

Now, we can calculate:

V1 = 0.34 L

Therefore, to prepare 0.34 M NH3(aq) from 15 M NH3(aq), you would need 0.34 L.