A boat moves through the water with two forces acting on it. One is a 2123 N forward push by the motor on the propeller, and the other is an 1930 N resistive force due to the water around the bow.
What is the acceleration of the 1345 Kg boat?
Answer in units of m/s^2
To find the acceleration of the boat, we need to apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The net force acting on the boat can be calculated by subtracting the resistive force from the forward push force:
Net force = Forward push force - Resistive force
Net force = 2123 N - 1930 N
Net force = 193 N
Now we can calculate the acceleration by dividing the net force by the mass of the boat:
Acceleration = Net force / Mass
Acceleration = 193 N / 1345 kg
Now, we can plug in the numbers to calculate the acceleration:
Acceleration = 0.1435 m/s^2
So, the acceleration of the boat is approximately 0.1435 m/s^2.
F1 = 2123 N.
F2 = 1930 N.
M = 1245 kg.
a = (F1-F2)/M.