4. Assuming that ball 1 was thrown with an initial velocity of 5 m/s, how far will it land away from the building horizontally?
A. 10 M
b. 16 M
C. 21 M
D. 0.63 M
5. A projectile is launched a t 35 m/s at an angle of 33 degrees. Determine (a) the maximum height of the projectile.
(B) the maximum distance of the projectile goes assuming it lands on the same horizontal plane. FREE RESPONSE
6.A Football player attempting to make a field goal that is 45 meters away kicks the ball at an angle of 50 degrees at 23 m/s? If the field goal posts are 3 m high, how much does the ball clear the goal posts by?
7. A football player attempting to make field goal kicks the ball with an initial velocity of 20 m/s. If the field goal is 35 meters away and 3 meters high determine the range of angles in which the field goal kicker will make the kick.
1. Cannot be determined. Height of fall is missing.
5. Break it into vertical and horizontal components, then using the vertical velocity
1/2 m vf^2=mgh solve for h.
. you have to solve two equations...
vertical:hf=hi+viv*t-4.9t^2
horizontal: 45=vih*t
solve for t in the second equation, then hf in the first. Then, subtract 3meters
7 same technique as in above
there is an answer for #4
explain 5 some more please
5. A projectile is launched a t 35 m/s at an angle of 33 degrees. Determine (a) the maximum height of the projectile.
(B) the maximum distance of the projectile goes assuming it lands on the same horizontal plane. FREE RESPONSE
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u = horizontal speed = 35 cos 33 the whole trip.
Vi = initial vertical speed = 35 sin 33
(1/2) m Vi^2 = m g h
so
h = Vi^2/(2*9.81)
find time to fall from h
the easy way is to say the average speed is (1/2) Vi because Vi at the bottom and 0 at the top
then rise time = fall time = H/.5Vi
so total time in air = H/Vi
then distance horizontal = range = u t
then rise time = fall time = H/.5Vi
so total time in air = 4 H/Vi