4. Assuming that ball 1 was thrown with an initial velocity of 5 m/s, how far will it land away from the building horizontally?
A. 10 M
b. 16 M
C. 21 M
D. 0.63 M
5. A projectile is launched a t 35 m/s at an angle of 33 degrees. Determine (a) the maximum height of the projectile.
(B) the maximum distance of the projectile goes assuming it lands on the same horizontal plane. FREE RESPONSE
6.A Football player attempting to make a field goal that is 45 meters away kicks the ball at an angle of 50 degrees at 23 m/s? If the field goal posts are 3 m high, how much does the ball clear the goal posts by?
7. A football player attempting to make field goal kicks the ball with an initial velocity of 20 m/s. If the field goal is 35 meters away and 3 meters high determine the range of angles in which the field goal kicker will make the kick.
A car slows down uniformly from a speed of 15.0 m/s to rest in 6.00 s .
4. Incomplete.
Vo = 35m/s[33o].
Xo = 35*Cos33 = 29.4 m/s.
Yo = 35*sin33 = 19.1 m/s.
5A. Yf^2 = Yo^2 + 2g*h.
Yf = 0.
g = -9.8 m/s^2.
h = ?
B. Dx = Vo^2*sin(2A)/g.
A = 33o.
g = +9.8 m/s^2.
Dx = ?
To solve these questions, we can use the equations of projectile motion. Here's a step-by-step guide on how to find the answers for each question:
4. To determine the horizontal distance the ball will land away from the building, we need to find the time it takes for the ball to reach the ground. We can use the equation:
d = v*t
Where d is the horizontal distance, v is the initial velocity, and t is the time.
The time it takes for the ball to reach the ground can be found using the equation:
t = √(2h / g)
Where h is the initial height (equal to the height of the building) and g is the acceleration due to gravity.
Once we have the time, we can calculate the horizontal distance using the equation:
d = v*cos(θ)*t
Where θ is the launch angle.
Plug in the values and calculate the result to find the answer.
5. (a) To find the maximum height of the projectile, we can use the formula:
h_max = (v^2*sin^2(θ)) / (2*g)
Where v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.
Plug in the values and calculate the result to find the answer.
(b) To find the maximum distance the projectile goes assuming it lands on the same horizontal plane, we can use the formula:
R = (v^2*sin(2*θ)) / g
Plug in the values and calculate the result to find the answer.
6. To determine how much the ball clears the goal posts, we need to find the maximum height reached by the ball. We can use the formula:
h_max = (v^2*sin^2(θ)) / (2*g)
Where v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.
Subtract the height of the goal posts from the maximum height to find the answer.
7. To determine the range of angles in which the field goal kicker will make the kick, we need to find the angle(s) at which the range (horizontal distance) is equal to or greater than the distance to the goal.
We can use the formula for horizontal distance:
R = (v^2*sin(2*θ)) / g
Rearrange the formula to solve for θ:
θ = (1/2)*asin((R*g) / v^2)
Plug in the values for R, g, and v, and calculate the result to find the range of angles. Note that there may be multiple angles that satisfy the condition.