A ball bearing at 22.0 Celsius is dropped into a cup containing 250.0 g of water at 20.0 Celsius. The water and ball bearing come to a temperature of 30.0 Celsius. What is the heat capacity of the ball bearing in J/Celsius?

How do I do this kind of question? I don't expect you to solve this, I just don't know the steps.

To find the heat capacity of the ball bearing, you can use the equation:

Q = mcΔT

Where:
Q = Heat transferred
m = Mass of the substance
c = Specific heat capacity of the substance
ΔT = Change in temperature

In this case, the heat is transferred from the ball bearing to the water. The water undergoes a temperature change from 20.0°C to 30.0°C.

1. Determine the mass of the ball bearing.
2. Calculate the heat transferred by the ball bearing to the water using the equation Q = mcΔT, where m is the mass of the ball bearing and ΔT is the temperature change (30.0°C - 20.0°C).
3. Divide the heat transferred by the temperature change to find the heat capacity of the ball bearing.

It is important to note that you will need the specific heat capacity of the ball bearing material to calculate its heat capacity accurately, as different substances have different specific heat capacities.