pls balance the equation

AL3C4+H2O-CH4+AL(OH)3

You have the formula wrong for aluminum carbide, Al4C3

To balance the given equation: AL3C4 + H2O → CH4 + AL(OH)3

We start by counting the number of atoms on each side of the equation:

On the left side (reactants):
- Aluminium (Al) atoms: 3
- Carbon (C) atoms: 4
- Hydrogen (H) atoms: 2
- Oxygen (O) atoms: 1

On the right side (products):
- Carbon (C) atoms: 1
- Hydrogen (H) atoms: 4
- Aluminium (Al) atoms: 1
- Oxygen (O) atoms: 3

To balance the equation, we need to adjust the coefficients in front of the reactants and products. Here's the step-by-step process:

1. Start by balancing the least abundant element first, in this case, Aluminium (Al):
- There are 3 Al atoms on the left side, so place a coefficient of 3 in front of Al(OH)3 on the right side: AL3C4 + H2O → CH4 + 3AL(OH)3

2. Next, balance the Carbon (C) atoms:
- There are 4 C atoms on the left side, so place a coefficient of 4 in front of CH4 on the right side: AL3C4 + H2O → 4CH4 + 3AL(OH)3

3. Balance the Hydrogen (H) atoms:
- There are 2 H atoms on the left side, so place a coefficient of 8 in front of H2O on the left side: AL3C4 + 8H2O → 4CH4 + 3AL(OH)3

4. Finally, balance the Oxygen (O) atoms:
- There are already 3 O atoms on the right side. To balance this, place a coefficient of 9 in front of H2O on the right side: AL3C4 + 8H2O → 4CH4 + 3AL(OH)3 + 9H2O

The balanced equation is:
AL3C4 + 8H2O → 4CH4 + 3AL(OH)3 + 9H2O